5x^2-4x+3=0

Solution for 5x^2-4x+3=0 equation:

Simplifying
5x2 + -4x + 3 = 0

Reorder the terms:
3 + -4x + 5x2 = 0

Solving
3 + -4x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.6 + -0.8x + x2 = 0

Move the constant term to the right:

Add '-0.6' to each side of the equation.
0.6 + -0.8x + -0.6 + x2 = 0 + -0.6

Reorder the terms:
0.6 + -0.6 + -0.8x + x2 = 0 + -0.6

Combine like terms: 0.6 + -0.6 = 0.0
0.0 + -0.8x + x2 = 0 + -0.6
-0.8x + x2 = 0 + -0.6

Combine like terms: 0 + -0.6 = -0.6
-0.8x + x2 = -0.6

The x term is -0.8x.  Take half its coefficient (-0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
-0.8x + 0.16 + x2 = -0.6 + 0.16

Reorder the terms:
0.16 + -0.8x + x2 = -0.6 + 0.16

Combine like terms: -0.6 + 0.16 = -0.44
0.16 + -0.8x + x2 = -0.44

Factor a perfect square on the left side:
(x + -0.4)(x + -0.4) = -0.44

Can't calculate square root of the right side.

The solution to this equation could not be determined.